6bbcafcd26
This is consistent with the behaviour in Adobe Reader.
320 lines
9.5 KiB
JavaScript
320 lines
9.5 KiB
JavaScript
/* Copyright 2017 Mozilla Foundation
|
|
*
|
|
* Licensed under the Apache License, Version 2.0 (the "License");
|
|
* you may not use this file except in compliance with the License.
|
|
* You may obtain a copy of the License at
|
|
*
|
|
* http://www.apache.org/licenses/LICENSE-2.0
|
|
*
|
|
* Unless required by applicable law or agreed to in writing, software
|
|
* distributed under the License is distributed on an "AS IS" BASIS,
|
|
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
|
|
* See the License for the specific language governing permissions and
|
|
* limitations under the License.
|
|
*/
|
|
|
|
import { Lexer, Linearization } from '../../src/core/parser';
|
|
import { FormatError } from '../../src/shared/util';
|
|
import { Name } from '../../src/core/primitives';
|
|
import { StringStream } from '../../src/core/stream';
|
|
|
|
describe('parser', function() {
|
|
describe('Lexer', function() {
|
|
it('should stop parsing numbers at the end of stream', function() {
|
|
var input = new StringStream('11.234');
|
|
var lexer = new Lexer(input);
|
|
var result = lexer.getNumber();
|
|
|
|
expect(result).toEqual(11.234);
|
|
});
|
|
|
|
it('should parse PostScript numbers', function() {
|
|
var numbers = ['-.002', '34.5', '-3.62', '123.6e10', '1E-5', '-1.', '0.0',
|
|
'123', '-98', '43445', '0', '+17'];
|
|
for (var i = 0, ii = numbers.length; i < ii; i++) {
|
|
var num = numbers[i];
|
|
var input = new StringStream(num);
|
|
var lexer = new Lexer(input);
|
|
var result = lexer.getNumber();
|
|
|
|
expect(result).toEqual(parseFloat(num));
|
|
}
|
|
});
|
|
|
|
it('should ignore double negative before number', function() {
|
|
var input = new StringStream('--205.88');
|
|
var lexer = new Lexer(input);
|
|
var result = lexer.getNumber();
|
|
|
|
expect(result).toEqual(-205.88);
|
|
});
|
|
|
|
it('should ignore minus signs in the middle of number', function() {
|
|
var input = new StringStream('205--.88');
|
|
var lexer = new Lexer(input);
|
|
var result = lexer.getNumber();
|
|
|
|
expect(result).toEqual(205.88);
|
|
});
|
|
|
|
it('should ignore line-breaks between operator and digit in number',
|
|
function() {
|
|
let minusInput = new StringStream('-\r\n205.88');
|
|
let minusLexer = new Lexer(minusInput);
|
|
|
|
expect(minusLexer.getNumber()).toEqual(-205.88);
|
|
|
|
let plusInput = new StringStream('+\r\n205.88');
|
|
let plusLexer = new Lexer(plusInput);
|
|
|
|
expect(plusLexer.getNumber()).toEqual(205.88);
|
|
});
|
|
|
|
it('should treat a single decimal point as zero', function() {
|
|
let input = new StringStream('.');
|
|
let lexer = new Lexer(input);
|
|
|
|
expect(lexer.getNumber()).toEqual(0);
|
|
|
|
let numbers = ['..', '-.', '+.', '-\r\n.', '+\r\n.'];
|
|
for (let number of numbers) {
|
|
let input = new StringStream(number);
|
|
let lexer = new Lexer(input);
|
|
|
|
expect(function() {
|
|
return lexer.getNumber();
|
|
}).toThrowError(FormatError, /^Invalid number:\s/);
|
|
}
|
|
});
|
|
|
|
it('should handle glued numbers and operators', function() {
|
|
var input = new StringStream('123ET');
|
|
var lexer = new Lexer(input);
|
|
var value = lexer.getNumber();
|
|
|
|
expect(value).toEqual(123);
|
|
// The lexer must not have consumed the 'E'
|
|
expect(lexer.currentChar).toEqual(0x45); // 'E'
|
|
});
|
|
|
|
it('should stop parsing strings at the end of stream', function() {
|
|
var input = new StringStream('(1$4)');
|
|
input.getByte = function(super_getByte) {
|
|
// simulating end of file using null (see issue 2766)
|
|
var ch = super_getByte.call(input);
|
|
return (ch === 0x24 /* '$' */ ? -1 : ch);
|
|
}.bind(input, input.getByte);
|
|
var lexer = new Lexer(input);
|
|
var result = lexer.getString();
|
|
|
|
expect(result).toEqual('1');
|
|
});
|
|
|
|
it('should not throw exception on bad input', function() {
|
|
// '8 0 2 15 5 2 2 2 4 3 2 4'
|
|
// should be parsed as
|
|
// '80 21 55 22 24 32'
|
|
var input = new StringStream('<7 0 2 15 5 2 2 2 4 3 2 4>');
|
|
var lexer = new Lexer(input);
|
|
var result = lexer.getHexString();
|
|
|
|
expect(result).toEqual('p!U"$2');
|
|
});
|
|
|
|
it('should ignore escaped CR and LF', function() {
|
|
// '(\101\<CR><LF>\102)'
|
|
// should be parsed as
|
|
// "AB"
|
|
var input = new StringStream('(\\101\\\r\n\\102\\\r\\103\\\n\\104)');
|
|
var lexer = new Lexer(input);
|
|
var result = lexer.getString();
|
|
|
|
expect(result).toEqual('ABCD');
|
|
});
|
|
|
|
it('should handle Names with invalid usage of NUMBER SIGN (#)', function() {
|
|
var inputNames = ['/# 680 0 R', '/#AQwerty', '/#A<</B'];
|
|
var expectedNames = ['#', '#AQwerty', '#A'];
|
|
|
|
for (var i = 0, ii = inputNames.length; i < ii; i++) {
|
|
var input = new StringStream(inputNames[i]);
|
|
var lexer = new Lexer(input);
|
|
var result = lexer.getName();
|
|
|
|
expect(result).toEqual(Name.get(expectedNames[i]));
|
|
}
|
|
});
|
|
});
|
|
|
|
describe('Linearization', function() {
|
|
it('should not find a linearization dictionary', function () {
|
|
// Not an actual linearization dictionary.
|
|
var stream1 = new StringStream(
|
|
'3 0 obj\n' +
|
|
'<<\n' +
|
|
'/Length 4622\n' +
|
|
'/Filter /FlateDecode\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
expect(Linearization.create(stream1)).toEqual(null);
|
|
|
|
// Linearization dictionary with invalid version number.
|
|
var stream2 = new StringStream(
|
|
'1 0 obj\n' +
|
|
'<<\n' +
|
|
'/Linearized 0\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
expect(Linearization.create(stream2)).toEqual(null);
|
|
});
|
|
|
|
it('should accept a valid linearization dictionary', function () {
|
|
var stream = new StringStream(
|
|
'131 0 obj\n' +
|
|
'<<\n' +
|
|
'/Linearized 1\n' +
|
|
'/O 133\n' +
|
|
'/H [ 1388 863 ]\n' +
|
|
'/L 90\n' +
|
|
'/E 43573\n' +
|
|
'/N 18\n' +
|
|
'/T 193883\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
var expectedLinearizationDict = {
|
|
length: 90,
|
|
hints: [1388, 863],
|
|
objectNumberFirst: 133,
|
|
endFirst: 43573,
|
|
numPages: 18,
|
|
mainXRefEntriesOffset: 193883,
|
|
pageFirst: 0,
|
|
};
|
|
expect(Linearization.create(stream)).toEqual(expectedLinearizationDict);
|
|
});
|
|
|
|
it('should reject a linearization dictionary with invalid ' +
|
|
'integer parameters', function () {
|
|
// The /L parameter should be equal to the stream length.
|
|
var stream1 = new StringStream(
|
|
'1 0 obj\n' +
|
|
'<<\n' +
|
|
'/Linearized 1\n' +
|
|
'/O 133\n' +
|
|
'/H [ 1388 863 ]\n' +
|
|
'/L 196622\n' +
|
|
'/E 43573\n' +
|
|
'/N 18\n' +
|
|
'/T 193883\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
expect(function () {
|
|
return Linearization.create(stream1);
|
|
}).toThrow(new Error('The "L" parameter in the linearization ' +
|
|
'dictionary does not equal the stream length.'));
|
|
|
|
// The /E parameter should not be zero.
|
|
var stream2 = new StringStream(
|
|
'1 0 obj\n' +
|
|
'<<\n' +
|
|
'/Linearized 1\n' +
|
|
'/O 133\n' +
|
|
'/H [ 1388 863 ]\n' +
|
|
'/L 84\n' +
|
|
'/E 0\n' +
|
|
'/N 18\n' +
|
|
'/T 193883\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
expect(function () {
|
|
return Linearization.create(stream2);
|
|
}).toThrow(new Error('The "E" parameter in the linearization ' +
|
|
'dictionary is invalid.'));
|
|
|
|
// The /O parameter should be an integer.
|
|
var stream3 = new StringStream(
|
|
'1 0 obj\n' +
|
|
'<<\n' +
|
|
'/Linearized 1\n' +
|
|
'/O /abc\n' +
|
|
'/H [ 1388 863 ]\n' +
|
|
'/L 89\n' +
|
|
'/E 43573\n' +
|
|
'/N 18\n' +
|
|
'/T 193883\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
expect(function () {
|
|
return Linearization.create(stream3);
|
|
}).toThrow(new Error('The "O" parameter in the linearization ' +
|
|
'dictionary is invalid.'));
|
|
});
|
|
|
|
it('should reject a linearization dictionary with invalid hint parameters',
|
|
function () {
|
|
// The /H parameter should be an array.
|
|
var stream1 = new StringStream(
|
|
'1 0 obj\n' +
|
|
'<<\n' +
|
|
'/Linearized 1\n' +
|
|
'/O 133\n' +
|
|
'/H 1388\n' +
|
|
'/L 80\n' +
|
|
'/E 43573\n' +
|
|
'/N 18\n' +
|
|
'/T 193883\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
expect(function () {
|
|
return Linearization.create(stream1);
|
|
}).toThrow(new Error('Hint array in the linearization dictionary ' +
|
|
'is invalid.'));
|
|
|
|
// The hint array should contain two, or four, elements.
|
|
var stream2 = new StringStream(
|
|
'1 0 obj\n' +
|
|
'<<\n' +
|
|
'/Linearized 1\n' +
|
|
'/O 133\n' +
|
|
'/H [ 1388 ]\n' +
|
|
'/L 84\n' +
|
|
'/E 43573\n' +
|
|
'/N 18\n' +
|
|
'/T 193883\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
expect(function () {
|
|
return Linearization.create(stream2);
|
|
}).toThrow(new Error('Hint array in the linearization dictionary ' +
|
|
'is invalid.'));
|
|
|
|
// The hint array should not contain zero.
|
|
var stream3 = new StringStream(
|
|
'1 0 obj\n' +
|
|
'<<\n' +
|
|
'/Linearized 1\n' +
|
|
'/O 133\n' +
|
|
'/H [ 1388 863 0 234]\n' +
|
|
'/L 93\n' +
|
|
'/E 43573\n' +
|
|
'/N 18\n' +
|
|
'/T 193883\n' +
|
|
'>>\n' +
|
|
'endobj'
|
|
);
|
|
expect(function () {
|
|
return Linearization.create(stream3);
|
|
}).toThrow(new Error('Hint (2) in the linearization dictionary ' +
|
|
'is invalid.'));
|
|
});
|
|
});
|
|
});
|