*This is a regression from PR 3424.* The PDF file in the referenced issue is using `Type3` fonts. In one of those, the `/CharProcs` dictionary contains an entry with the name `/#`. Before the changes to `Lexer_getName` in PR 3424, we were allowing certain invalid `Name` patterns containing the NUMBER SIGN (#). It's unfortunate that this has been broken for close to two and a half years before the bug surfaced, but it should at least indicate that this is not a widespread issue. Fixes 6692.
		
			
				
	
	
		
			266 lines
		
	
	
		
			7.7 KiB
		
	
	
	
		
			JavaScript
		
	
	
	
	
	
			
		
		
	
	
			266 lines
		
	
	
		
			7.7 KiB
		
	
	
	
		
			JavaScript
		
	
	
	
	
	
/* globals expect, it, describe, StringStream, Lexer, Name, Linearization */
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'use strict';
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describe('parser', function() {
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  describe('Lexer', function() {
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    it('should stop parsing numbers at the end of stream', function() {
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      var input = new StringStream('11.234');
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      var lexer = new Lexer(input);
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      var result = lexer.getNumber();
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      expect(result).toEqual(11.234);
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    });
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    it('should parse PostScript numbers', function() {
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      var numbers = ['-.002', '34.5', '-3.62', '123.6e10', '1E-5', '-1.', '0.0',
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                    '123', '-98', '43445', '0', '+17'];
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      for (var i = 0, ii = numbers.length; i < ii; i++) {
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        var num = numbers[i];
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        var input = new StringStream(num);
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        var lexer = new Lexer(input);
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        var result = lexer.getNumber();
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        expect(result).toEqual(parseFloat(num));
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      }
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    });
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    it('should ignore double negative before number', function() {
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      var input = new StringStream('--205.88');
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      var lexer = new Lexer(input);
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      var result = lexer.getNumber();
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      expect(result).toEqual(-205.88);
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    });
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    it('should handle glued numbers and operators', function() {
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      var input = new StringStream('123ET');
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      var lexer = new Lexer(input);
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      var value = lexer.getNumber();
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      expect(value).toEqual(123);
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      // The lexer must not have consumed the 'E'
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      expect(lexer.currentChar).toEqual(0x45); // 'E'
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    });
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    it('should stop parsing strings at the end of stream', function() {
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      var input = new StringStream('(1$4)');
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      input.getByte = function(super_getByte) {
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        // simulating end of file using null (see issue 2766)
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        var ch = super_getByte.call(input);
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        return (ch === 0x24 /* '$' */ ? -1 : ch);
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      }.bind(input, input.getByte);
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      var lexer = new Lexer(input);
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      var result = lexer.getString();
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      expect(result).toEqual('1');
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    });
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    it('should not throw exception on bad input', function() {
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      // '8 0 2 15 5 2 2 2 4 3 2 4'
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      // should be parsed as
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      // '80 21 55 22 24 32'
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      var input = new StringStream('<7 0 2 15 5 2 2 2 4 3 2 4>');
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      var lexer = new Lexer(input);
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      var result = lexer.getHexString();
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      expect(result).toEqual('p!U"$2');
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    });
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    it('should ignore escaped CR and LF', function() {
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      // '(\101\<CR><LF>\102)'
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      // should be parsed as
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      // "AB"
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      var input = new StringStream('(\\101\\\r\n\\102\\\r\\103\\\n\\104)');
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      var lexer = new Lexer(input);
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      var result = lexer.getString();
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      expect(result).toEqual('ABCD');
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    });
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    it('should handle Names with invalid usage of NUMBER SIGN (#)', function() {
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      var inputNames = ['/# 680 0 R', '/#AQwerty', '/#A<</B'];
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      var expectedNames = ['#', '#AQwerty', '#A'];
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      for (var i = 0, ii = inputNames.length; i < ii; i++) {
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        var input = new StringStream(inputNames[i]);
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        var lexer = new Lexer(input);
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        var result = lexer.getName();
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        expect(result).toEqual(Name.get(expectedNames[i]));
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      }
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    });
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  });
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  describe('Linearization', function() {
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    it('should not find a linearization dictionary', function () {
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      // Not an actual linearization dictionary.
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      var stream1 = new StringStream(
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        '3 0 obj\n' +
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        '<<\n' +
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        '/Length 4622\n' +
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        '/Filter /FlateDecode\n' +
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        '>>\n' +
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        'endobj'
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      );
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      expect(Linearization.create(stream1)).toEqual(null);
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      // Linearization dictionary with invalid version number.
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      var stream2 = new StringStream(
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        '1 0 obj\n' +
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        '<<\n' +
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        '/Linearized 0\n' +
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        '>>\n' +
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        'endobj'
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      );
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      expect(Linearization.create(stream2)).toEqual(null);
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    });
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    it('should accept a valid linearization dictionary', function () {
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      var stream = new StringStream(
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        '131 0 obj\n' +
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        '<<\n' +
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        '/Linearized 1\n' +
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        '/O 133\n' +
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        '/H [ 1388 863 ]\n' +
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        '/L 90\n' +
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        '/E 43573\n' +
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        '/N 18\n' +
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        '/T 193883\n' +
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        '>>\n' +
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        'endobj'
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      );
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      var expectedLinearizationDict = {
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        length: 90,
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        hints: [1388, 863],
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        objectNumberFirst: 133,
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        endFirst: 43573,
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        numPages: 18,
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        mainXRefEntriesOffset: 193883,
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        pageFirst: 0,
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      };
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      expect(Linearization.create(stream)).toEqual(expectedLinearizationDict);
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    });
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    it('should reject a linearization dictionary with invalid ' +
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       'integer parameters', function () {
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      // The /L parameter should be equal to the stream length.
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      var stream1 = new StringStream(
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        '1 0 obj\n' +
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        '<<\n' +
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        '/Linearized 1\n' +
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        '/O 133\n' +
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        '/H [ 1388 863 ]\n' +
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        '/L 196622\n' +
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        '/E 43573\n' +
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        '/N 18\n' +
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        '/T 193883\n' +
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        '>>\n' +
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        'endobj'
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      );
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      expect(function () {
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        return Linearization.create(stream1);
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      }).toThrow(new Error('The "L" parameter in the linearization ' +
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                           'dictionary does not equal the stream length.'));
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      // The /E parameter should not be zero.
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      var stream2 = new StringStream(
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        '1 0 obj\n' +
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        '<<\n' +
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        '/Linearized 1\n' +
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        '/O 133\n' +
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        '/H [ 1388 863 ]\n' +
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        '/L 84\n' +
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        '/E 0\n' +
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        '/N 18\n' +
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        '/T 193883\n' +
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        '>>\n' +
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        'endobj'
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      );
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      expect(function () {
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        return Linearization.create(stream2);
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      }).toThrow(new Error('The "E" parameter in the linearization ' +
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                           'dictionary is invalid.'));
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      // The /O parameter should be an integer.
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      var stream3 = new StringStream(
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        '1 0 obj\n' +
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        '<<\n' +
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        '/Linearized 1\n' +
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        '/O /abc\n' +
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        '/H [ 1388 863 ]\n' +
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        '/L 89\n' +
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        '/E 43573\n' +
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        '/N 18\n' +
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        '/T 193883\n' +
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        '>>\n' +
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        'endobj'
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      );
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      expect(function () {
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        return Linearization.create(stream3);
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      }).toThrow(new Error('The "O" parameter in the linearization ' +
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                           'dictionary is invalid.'));
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    });
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    it('should reject a linearization dictionary with invalid hint parameters',
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       function () {
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      // The /H parameter should be an array.
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      var stream1 = new StringStream(
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        '1 0 obj\n' +
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        '<<\n' +
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        '/Linearized 1\n' +
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        '/O 133\n' +
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        '/H 1388\n' +
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        '/L 80\n' +
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        '/E 43573\n' +
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        '/N 18\n' +
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        '/T 193883\n' +
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        '>>\n' +
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        'endobj'
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      );
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      expect(function () {
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        return Linearization.create(stream1);
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      }).toThrow(new Error('Hint array in the linearization dictionary ' +
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                           'is invalid.'));
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      // The hint array should contain two, or four, elements.
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      var stream2 = new StringStream(
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        '1 0 obj\n' +
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        '<<\n' +
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        '/Linearized 1\n' +
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        '/O 133\n' +
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        '/H [ 1388 ]\n' +
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        '/L 84\n' +
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        '/E 43573\n' +
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        '/N 18\n' +
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        '/T 193883\n' +
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        '>>\n' +
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        'endobj'
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      );
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      expect(function () {
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        return Linearization.create(stream2);
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      }).toThrow(new Error('Hint array in the linearization dictionary ' +
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                           'is invalid.'));
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      // The hint array should not contain zero.
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      var stream3 = new StringStream(
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        '1 0 obj\n' +
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        '<<\n' +
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        '/Linearized 1\n' +
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        '/O 133\n' +
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        '/H [ 1388 863 0 234]\n' +
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        '/L 93\n' +
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        '/E 43573\n' +
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        '/N 18\n' +
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        '/T 193883\n' +
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        '>>\n' +
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        'endobj'
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      );
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      expect(function () {
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        return Linearization.create(stream3);
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      }).toThrow(new Error('Hint (2) in the linearization dictionary ' +
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                           'is invalid.'));
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    });
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  });
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});
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