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Simplify the decodeFontData/encodeFontData font-test helper functions

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We can (and in my opinion should) use the standard `atob`/`btoa` functions, rather than manually re-implementing this functionality for the font-tests.
This commit is contained in:
Jonas Jenwald 2022-02-25 11:30:22 +01:00
parent 889b761f22
commit f4e78d9b38
1 changed files with 5 additions and 44 deletions
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49
test/font/fontutils.js
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@ -14,55 +14,16 @@
* limitations under the License. * limitations under the License.
*/ */
const base64alphabet = import { bytesToString, stringToBytes } from "../../src/shared/util.js";
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";
function decodeFontData(base64) { function decodeFontData(base64) {
const result = []; const str = atob(base64);
return stringToBytes(str);
let bits = 0,
bitsLength = 0;
for (let i = 0, ii = base64.length; i < ii; i++) {
const ch = base64[i];
if (ch <= " ") {
continue;
}
const index = base64alphabet.indexOf(ch);
if (index < 0) {
throw new Error("Invalid character");
}
if (index >= 64) {
break;
}
bits = (bits << 6) | index;
bitsLength += 6;
if (bitsLength >= 8) {
bitsLength -= 8;
const code = (bits >> bitsLength) & 0xff;
result.push(code);
}
}
return new Uint8Array(result);
} }
function encodeFontData(data) { function encodeFontData(data) {
let buffer = ""; const str = bytesToString(data);
let i, n; return btoa(str);
for (i = 0, n = data.length; i < n; i += 3) {
const b1 = data[i] & 0xff;
const b2 = data[i + 1] & 0xff;
const b3 = data[i + 2] & 0xff;
const d1 = b1 >> 2,
d2 = ((b1 & 3) << 4) | (b2 >> 4);
const d3 = i + 1 < n ? ((b2 & 0xf) << 2) | (b3 >> 6) : 64;
const d4 = i + 2 < n ? b3 & 0x3f : 64;
buffer +=
base64alphabet.charAt(d1) +
base64alphabet.charAt(d2) +
base64alphabet.charAt(d3) +
base64alphabet.charAt(d4);
}
return buffer;
} }
async function ttx(data) { async function ttx(data) {